Independent Samples t-Test (or 2-Sample t-Test) - PowerPoint PPT Presentation

Independent Samples t-Test (or 2-Sample t-Test)

Description:

Independent Samples t-Test (or 2-Sample t-Test) Advanced Research Methods in Psychology - lecture - Matthew Rockloff When to use the independent samples t-test The . – PowerPoint PPT presentation

Number of Views:320

Avg rating: 3.0/5.0

Slides: 38

Provided by: psychology76

Category:

Tags: independent | sample | samples | test

Transcript and Presenter's Notes

Title: Independent Samples t-Test (or 2-Sample t-Test)

• Advanced Research Methods in Psychology
• - lecture -
• Matthew Rockloff

• The independent samples t-test is probably the
  single most widely used test in statistics.
• It is used to compare differences between
  separate groups.
• In Psychology, these groups are often composed by
  randomly assigning research participants to
  conditions.
• However, this test can also be used to explore
  differences in naturally occurring groups.
• For example, we may be interested in differences
  of emotional intelligence between males and
  females.

• Any differences between groups can be explored
  with the independent t-test, as long as the
  tested members of each group are reasonably
  representative of the population. 1
• 1 There are some technical requirements as
  well. Principally, each variable must come from
  a normal (or nearly normal) distribution.

• Suppose we put people on 2 diets the pizza
  diet and the beer diet.
• Participants are randomly assigned to either
  1-week of eating exclusively pizza or 1-week of
  exclusively drinking beer.
• Of course, this would be unethical, because pizza
  and beer should always be consumed together, but
  this is just an example.

• At the end of the week, we measureweight gain by
  each participant.
• Which diet causes more weight gain?
• In other words, the null hypothesis is
• Ho wt. gain pizza diet wt. gain beer diet.

• Why?
• The null hypothesis is the opposite of what we
  hope to find.
• In this case, our research hypothesis is that
  there ARE differences between the 2 diets.
• Therefore, our null hypothesis is that there are
  NO differences between these 2 diets.

• The first step in calculating the independent
  samples t-test is to calculate the variance and
  mean in each condition.
• In the previous example, there are a total of 10
  people, with 5 in each condition.
• Since there are different people in each
  condition, these samples are independent of
  one another giving rise to the name of the
  test.

• The variances and means are calculated separately
  for each condition (Pizza and Beer).
• A streamlined calculation of the variance for
  each condition was illustrated previously. (See
  Slide 7.)
• In short, we take each observed weight gain for
  the pizza condition, subtract it from the mean
  gain of the pizza dieters ( 2) and square
  the result (see column 3).

• Next, add up column 3 and divide by the number of
  participants in that condition (n1 5) to get
  the sample variance,
• The same calculations are repeated for the beer
  condition.

• The formula for the independent samples t-test
  is

• From the calculations previously, we have
  everything that is needed to find the t.

• The t is calculated under the assumption,
  called the null hypothesis, that there are no
  differences between the pizza and beer diet.
• If this were true, when we repeatedly sample 10
  people from the population and put them in our 2
  diets, most often we would calculate a t of
  0.

• Look again at the formula for the t.
• Most often the numerator (X1-X2) will be 0,
  because the mean of the two conditions should be
  the same under the null hypothesis.
• That is, weight gain is the same under both the
  pizza and beer diet.

• Sometimes the weight gain might be a bit higher
  under the pizza diet, leading to a positive t
  value.
• In other samples of 10 people, weight gain might
  be a little higher under the beer diet, leading
  to a negative t value.
• The important point, however, is that under the
  null hypothesis we should expect that most t
  values that we compute are close to 0.

• Our computed t-value is not 0, but it is in
  fact negative (t(8) -4.47).
• Although the t-value is negative, this should not
  bother us.
• Remember that the t-value is only - 4.47 because
  we named the pizza diet X1 and the beer diet X2.
• This is, of course, completely arbitrary.
• If we had reversed our order of calculation, with
  the pizza diet as X2 and the beer diet as X1,
  then our calculated t-value would be positive
  4.47.

• The calculated t-value is 4.47 (notice, Ive
  eliminated the unnecessary - sign), and the
  degrees of freedom are 8.
• In the research question we did not specify which
  diet should cause more weight gain, therefore
  this t-test is a so-called 2-tailed t.

• In the last step, we need to find the critical
  value for a 2-tailed t with 8 degrees of
  freedom.
• This is available from tables that are in the
  back of any Statistics textbook.
• Look in the back for Critical Values of the
  t-distribution, or something similar.
• The value you should find is C.V. t(8),
  2-tailed 2.31.

• The calculated t-value of 4.47 is larger in
  magnitude than the C.V. of 2.31, therefore we can
  reject the null hypothesis.
• Even for a results section of journal article,
  this language is a bit too formal and general. It
  is more important to state the research result,
  namely
• Participants on the Beer diet (M 4.00) gained
  significantly more weight than those on the Pizza
  diet (M 2.00), t(8) 4.47, p lt .05
  (two-tailed).

• Repeat from previous slideParticipants on the
  Beer diet (M 4.00) gained significantly more
  weight than those on the Pizza diet (M 2.00),
  t(8) 4.47, p lt .05 (two-tailed).
• Making this conclusion requires inspection of the
  mean scores for each condition (Pizza and Beer).

• First, the variables must be setup in the SPSS
  data editor.
• We need to include both the independent and
  dependent variables.
• Although it is not strictly necessary, it is good
  practice to give each person a unique code
  (e.g., personid)

• In the previous example
• Dependent Variable wtgain (or weight gain)
• Independent Variable diet
• Why?
• The independent variable (diet) causes changes in
  the dependent variable (weight gain).

• Next, we need to provide codes that distinguish
  between the 2 types of diets.
• By clicking in the grey box of the Label field
  in the row containing the diet variable, we get
  a pop-up dialog that allows us to code the diet
  variable.
• Arbitrarily, the pizza diet is coded as diet 1
  and the beer diet is diet 2.
• Any other 2 codes would work, but these suffice
• See next slide.

• Moving to the data view tab of the SPSS editor,
  the data is entered.
• Each participant is entered on a separate line a
  code is entered for the diet they were on (1
  Pizza, 2 Beer) and the weight gain of each is
  entered, as follows ?

• Moving to the data view tab of the SPSS editor,
  the data is entered.
• Each participant is entered on a separate line a
  code is entered for the diet they were on (1
  Pizza, 2 Beer) and the weight gain of each is
  entered, as follows ?

• Moving to the data view tab of the SPSS editor,
  the data is entered.
• Each participant is entered on a separate line a
  code is entered for the diet they were on (1
  Pizza, 2 Beer) and the weight gain of each is
  entered, as follows ?

• Next, the command syntax for an independent
  t-test must be entered into the command editor.
• The format for the command is as follows
• t-test groups IndependentVariable(Level1,Level2)
• variablesDependentVariable.
• You must substitute the names of the independent
  and dependent variables, as well as the codes for
  the 2 levels of the independent variable. In our
  example, the syntax should be as per the next
  slide ?

• SPSS gives the means for each of the conditions
  (Pizza Mean 2 and Beer Mean 4).
• In addition, SPSS provides a t-value of -4.47
  with 8 degrees of freedom.
• These are the same figures that were computed by
  hand previously.
• However, SPSS does not provide a critical value.
• Instead, an exact probability is provided (p
  .002).

• As long as this p-value falls below the standard
  of .05, we can declare a significant difference
  between our mean values.
• Since .002 is below .05 we can conclude
• Participants on the Beer diet (M 4.00) gained
  significantly more weight than those on the
  Pizza diet (M 2.00), t(8) 4.47, p lt .01
  (two-tailed).

• Repeat from previous slideParticipants on the
  Beer diet (M 4.00) gained significantly more
  weight than those on the Pizza diet (M 2.00),
  t(8) 4.47, p lt .01 (two-tailed).
• In APA style we normally only display
  significance to 2 significant digits.
• Therefore, the probability is displayed as
  plt.01, which is the smallest probability within
  this range of accuracy.

• The SPSS output also displays Levenes Test for
  Equality of Variances (see the first 2 columns in
  second table on slide 30).
• Why?
• Strictly speaking, the t-test is only valid if we
  have approximately equal variances within each of
  our two groups.
• In our example, this was not a problem because
  the 2 variances were exactly equal (Variance
  Pizza 0.04 and Variance Beer 0.04).

• However, if this test is significant, meaning
  that the p-value given is less than .05, then
  we should choose the bottom line when
  interpreting our results.
• This bottom line makes slight adjustments to the
  t-test to accountfor problems when there are not
  equal variances in both conditions.

• The practical importance of this distinction is
  small.
• Even if variances are not equal between
  conditions, the hand calculations we have shown
  will most often lead to the correct conclusion
  anyway, and use of the top line is almost
  always appropriate.

• Advanced Research Methods in Psychology
• - Week 2 lecture -
• Matthew Rockloff